Calculus Prelude · free preview

3.3 The special number

Why can every exponential function of form $f(t) = b^t$ (where $b \gt 0$ and $b \ne 1$) be thought of as a horizontal scaling of a single special exponential function?

1. Introduction

Introduction

2. The natural base

The natural base

3. Why any exponential function can be written in terms of

Why any exponential function can be written in terms of

4. Summary

Summary

5. Open a new **Desmos*…

Open a new Desmos worksheet and define the following functions: f(t)=2tf(t) = 2^t, g(t)=3tg(t) = 3^t, h(t)=(13)th(t) = (\frac{1}{3})^t, and p(t)=f(kt)p(t) = f(kt). After you define pp, accept the slider for kk, and set the range of the slider to be −2≤k≤2-2 \le k \le 2.

By experimenting with the value of kk, find a value of kk so that the graph of p(t)=f(kt)=2ktp(t) = f(kt) = 2^{kt} appears to align with the graph of g(t)=3tg(t) = 3^t. What is the value of kk?

6. What is the meaning …

What is the meaning of A(0.5)A(0.5) in terms of the function ff and its graph?

7. Compute the value of…

Compute the value of A(h)A(h) for at least 66 different small values of hh, both positive and negative. For instance, one value to try might be h=0.0001h = 0.0001. Record a table of your results.

8. What do you notice a…

What do you notice about the values you found in (b)? How do they compare to an important number?

9. Explain why the foll…

Explain why the following sentence makes sense: “The function ete^t is increasing at an average rate that is about the same as its value on small intervals near t=1t = 1.”

10. Adjust your definiti…

Adjust your definition of AA in Desmos by changing 11 to 22 so that

A(h)=f(2+h)−f(2)hA(h) = \frac{f(2+h)-f(2)}{h}

. How does the value of A(h)A(h) compare to f(2)f(2) for small values of hh?

11. $e^t = 2$…

et=2e^t = 2

12. $e^{3t} = 5$…

e3t=5e^{3t} = 5

13. $2e^t - 4 = 7$…

2et−4=72e^t - 4 = 7

14. $3e^{0.25t} + 2 = 6$…

3e0.25t+2=63e^{0.25t} + 2 = 6

15. $4 - 2e^{-0.7t} = 3$…

4−2e−0.7t=34 - 2e^{-0.7t} = 3

16. $2e^{1.2t} = 1.5e^{1…$

2e1.2t=1.5e1.6t2e^{1.2t} = 1.5e^{1.6t}

17. When a single invest…

When a single investment of principal, $PP, is invested in an account that returns interest at an annual rate of rr (a decimal that corresponds to the percentage rate, such as r=0.05r = 0.05 corresponding to 55%) that is compounded nn times per year, the amount of money in the account after tt years is given by A(t)=P(1+rn)ntA(t) = P(1 + \frac{r}{n})^{nt}.

Suppose we invest $100100 in an account that earns 88% annual interest. We investigate the effects of different rates of compounding.

  • Compute A(1)A(1) if interest is compounded quarterly (n=4n = 4). - Compute A(1)A(1) if interest is compounded monthly. - Compute A(1)A(1) if interest is compounded weekly. - Compute A(1)A(1) if interest is compounded daily. - If we let the number of times that interest is compounded increase without bound, we say that the interest is “compounded continuously”. When interest is compounded continuously, it turns out that the amount of money an account with initial investment $PP after tt years at an annual interest rate of rr is A(t)=PertA(t) = Pe^{rt}, where ee is the natural base. Compute A(1)A(1) in the same context as the preceding questions but where interest is compounded continuously. - How much of a difference does continuously compounded interest make over interest compounded quarterly in one year's time? How does your answer change over 2525 years' time?

18. In **Desmos**

In Desmos, define the function g(t)=ektg(t) = e^{kt} and accept the slider for kk. Set the range of the slider to −2≤k≤2-2 \le k \le 2, and assume that k≠0k \ne 0. Experiment with a wide range of values of kk to see the effects of changing kk.

  • For what values of kk is gg always increasing? For what values of kk is gg always decreasing? - For which value of kk is the average rate of change of gg on [0,1][0,1] greater: when k=−0.1k = -0.1 or when k=−0.05k = -0.05? - What is the long-term behavior of gg when k<0k \lt 0? Why does this occur? - Experiment with the slider to find a value of kk for which g(2)=12g(2) = \frac{1}{2}. Test your estimate by computing e2ke^{2k}. How accurate is your estimate?

19. A can of soda is rem…

A can of soda is removed from a refrigerator at time t=0t = 0 (in minutes) and its temperature, F(t)F(t), in degrees Fahrenheit, is computed at regular intervals. Based on the data, a model is formulated for the object's temperature, given by

F(t)=74.4−38.8e−0.05tF(t) = 74.4 - 38.8e^{-0.05t}

.

  • What is the long-term behavior of the function g(t)=e−0.05tg(t) = e^{-0.05t}? Why? - What is the long-term behavior of the function F(t)=74.4−38.8e−0.05tF(t) = 74.4 - 38.8e^{-0.05t}? What is the meaning of this value in the physical context of the problem? - What is the temperature of the refrigerator? Why? - Compute the average rate of change of FF on the intervals [10,20][10,20], [20,30][20,30], and [30,40][30,40]. Write a careful sentence, with units, to explain the meaning of each, and write an additional sentence to describe any overall trends in how the average rate of change of FF is changing.

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