微积分I(标准路径) · free preview

§8.3 Geometric sums

什么是有限几何和?无论和中有多少项,我们如何快速求出它的值?

1. Introduction

Introduction

2. Finite Geometric Series

Finite Geometric Series

3. Infinite Geometric Series

Infinite Geometric Series

4. Let's explore sums o…

Let's explore sums of the form

Sn=1+12+(12)2+(12)3+⋯+(12)n−1S_n = 1 + \frac{1}{2} + \left( \frac{1}{2} \right)^2 + \left( \frac{1}{2} \right)^3 + \cdots + \left( \frac{1}{2} \right)^{n-1}

. Observe that we can think of the first term, 11, as (12)0(\frac{1}{2})^0, and since the powers of 12\frac{1}{2} include every whole number from 00 to n−1n-1, there are exactly nn terms in the sum given by SnS_n.

Note that S1=1S_1 = 1, S2=S1+12=1+12=32S_2 = S_1 + \frac{1}{2} = 1 + \frac{1}{2} = \frac{3}{2}, and S3=S2+14=32+14=74S_3 = S_2 + \frac{1}{4} = \frac{3}{2} + \frac{1}{4} = \frac{7}{4}. Using the fact that each subsequent value of SnS_n can be computed by adding one additional term to the preceding sum, complete Table with the exact (fractional) value of each sum.

n=1n=1 | S1=1S_1 = 1

n=2n=2 | S2=32S_2 = \frac{3}{2}

n=3n=3 | S3=74S_3 = \frac{7}{4}

n=4n=4 | S4=S_4 =

n=5n=5 | S5=S_5 =

n=6n=6 | S6=S_6 =

n=7n=7 | S7=S_7 =

5. Multiply both sides …

Multiply both sides of Equation by r=25r = \frac{2}{5}. Write the new equation in the form

25⋅Sn=\frac{2}{5} \cdot S_n =

.

6. Now subtract Equatio…

Now subtract Equation from Equation, and explain why it follows that

Sn−25⋅Sn=1−(25)nS_n - \frac{2}{5} \cdot S_n = 1 - \left(\frac{2}{5}\right)^{n}

.

7. Solve Equation for $…$

Solve Equation for SnS_n to find a simple formula for SnS_n that does not involve adding nn terms.

8. How would your work …

How would your work above change if instead of the original geometric sum SnS_n, we considered the situation with a=7a = 7,

Sn=7+7⋅25+7⋅(25)2+⋯+7⋅(25)n−1S_n = 7 + 7 \cdot \frac{2}{5} + 7 \cdot \left(\frac{2}{5}\right)^2 + \cdots + 7 \cdot \left(\frac{2}{5}\right)^{n-1}

?

9. Use the shortcut for…

Use the shortcut formula in Equation to find the exact value of the finite geometric series

1+12+(12)2+(12)3+⋯+(12)91 + \frac{1}{2} + \left( \frac{1}{2} \right)^2 + \left( \frac{1}{2} \right)^3 + \cdots + \left( \frac{1}{2} \right)^9

.

10. Use the shortcut for…

Use the shortcut formula in Equation to find the exact value of the finite geometric series

2−83+329−12827+⋯+2⋅(−43)72 - \frac{8}{3} + \frac{32}{9} - \frac{128}{27} + \cdots + 2 \cdot \left( -\frac{4}{3} \right)^7

.

11. Use the shortcut for…

Use the shortcut formula in Equation to find the exact value of the finite geometric series

13+1+3+9+⋯+6561\frac{1}{3} + 1 + 3 + 9 + \cdots + 6561

.

12. Can we find the valu…

Can we find the value of

1+12+(12)2+(12)3+⋯1 + \frac{1}{2} + \left( \frac{1}{2} \right)^2 + \left( \frac{1}{2} \right)^3 + \cdots

, where the sum never terminates?

13. $1 + \frac{1}{3} + \…$

1+13+19+127+⋯1 + \frac{1}{3} + \frac{1}{9} + \frac{1}{27} + \cdots

14. $4 - 2 + 1 - \frac{1…$

4−2+1−12+14−⋯4 - 2 + 1 - \frac{1}{2} + \frac{1}{4} - \cdots

15. $2 + \frac{8}{3} + \…$

2+83+329+12827+⋯2 + \frac{8}{3} + \frac{32}{9} + \frac{128}{27} + \cdots

16. $\sum_{k = 0}^{\inft…$

∑k=0∞5⋅(34)k\sum_{k = 0}^{\infty} 5 \cdot \left( \frac{3}{4} \right)^k

17. $\sum_{k = 1}^{\inft…$

∑k=1∞−2⋅(−23)k\sum_{k = 1}^{\infty} -2 \cdot \left( -\frac{2}{3} \right)^k

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