微积分I(标准路径) · free preview

§5.5 Other options for finding algebraic antiderivatives

部分分式法如何使任何有理函数都能被求出原函数?

1. Introduction

Introduction

2. The Method of Partial Fractions

The Method of Partial Fractions

3. Using an Integral Table

Using an Integral Table

4. Using Computer Algebra Systems

Using Computer Algebra Systems

5. Summary

Summary

6. For each of the inde…

For each of the indefinite integrals below, the main question is to decide whether the integral can be evaluated using uu-substitution, integration by parts, a combination of the two, or neither. For integrals for which your answer is affirmative, state the substitution(s) you would use. It is not necessary to actually evaluate any of the integrals completely, unless the integral can be evaluated immediately using a familiar basic antiderivative.

∫x2sin⁡(x3) dx\displaystyle \int x^2 \sin(x^3) \, dx, ∫x2sin⁡(x) dx\displaystyle \int x^2 \sin(x) \, dx, ∫sin⁡(x3) dx\displaystyle \int \sin(x^3) \, dx, ∫x5sin⁡(x3) dx\displaystyle \int x^5 \sin(x^3) \, dx

7. Evaluate $$\int \fr…

Evaluate

∫5xx2−x−2 dx\int \frac{5x}{x^2-x-2} \, dx

.

8. $\displaystyle \int …$

∫1x2−2x−3 dx\displaystyle \int \frac{1}{x^2 - 2x - 3} \, dx, given that 1x2−2x−3=1/4x−3−1/4x+1\displaystyle \frac{1}{x^2 - 2x - 3} = \frac{1/4}{x-3} - \frac{1/4}{x+1}

9. $\displaystyle \int …$

∫x2+1x3−x2 dx\displaystyle \int \frac{x^2+1}{x^3 - x^2} \, dx, given that x2+1x3−x2=−1x−1x2+2x−1\displaystyle \frac{x^2+1}{x^3 - x^2} = -\frac{1}{x} - \frac{1}{x^2} + \frac{2}{x-1}

10. $\displaystyle \int …$

∫x−2x4+x2 dx\displaystyle \int \frac{x-2}{x^4 + x^2}\, dx, given that x−2x4+x2=1x−2x2+−x+21+x2\displaystyle \frac{x-2}{x^4 + x^2} = \frac{1}{x} - \frac{2}{x^2} + \frac{-x+2}{1+x^2}

11. Evaluate the integra…

Evaluate the integral

∫9+64x2 dx\int \sqrt{9 + 64x^2} \, dx

.

12. $\displaystyle \int …$

∫x2+4 dx\displaystyle \int \sqrt{x^2 + 4} \, dx

13. $\displaystyle \int …$

∫xx2+4 dx\displaystyle \int \frac{x}{\sqrt{x^2 +4}} \, dx

14. $\displaystyle \int …$

∫216+25x2 dx\displaystyle \int \frac{2}{\sqrt{16+25x^2}}\, dx

15. $\displaystyle \int …$

∫1x249−36x2 dx\displaystyle \int \frac{1}{x^2 \sqrt{49-36x^2}} \, dx

16. For each of the foll…

For each of the following integrals involving rational functions, (1) use a CAS to find the partial fraction decomposition of the integrand; (2) evaluate the integral of the resulting function without the assistance of technology; (3) use a CAS to evaluate the original integral to test and compare your result in (2). -∫x3+x+1x4−1 dx\int \frac{x^3 + x + 1}{x^4 - 1} \, dx-∫x5+x2+3x3−6x2+11x−6 dx\int \frac{x^5 + x^2 + 3}{x^3 - 6x^2 + 11x - 6} \, dx-∫x2−x−1(x−3)3 dx\int \frac{x^2 - x - 1}{(x-3)^3} \, dx

17. For each of the foll…

For each of the following integrals involving radical functions, (1) use an appropriate uu-substitution along with Appendix to evaluate the integral without the assistance of technology, and (2) use a CAS to evaluate the original integral to test and compare your result in (1). -∫1x9x2+25 dx\int \frac{1}{x \sqrt{9x^2 + 25}} \, dx-∫x1+x4 dx\int x \sqrt{1 + x^4} \, dx-∫ex4+e2x dx\int e^x \sqrt{4 + e^{2x}} \, dx-∫tan⁡(x)9−cos⁡2(x) dx\int \frac{\tan(x)}{\sqrt{9 - \cos^2(x)}} \, dx

18. Consider the indefin…

Consider the indefinite integral given by

∫x+1+x2x dx\int \frac{\sqrt{x+\sqrt{1+x^2}}}{x} \, dx

. - Explain why uu-substitution does not offer a way to simplify this integral by discussing at least two different options you might try for uu. - Explain why integration by parts does not seem to be a reasonable way to proceed, either, by considering one option for uu and dvdv. - Is there any line in the integral table in Appendix that is helpful for this integral? - Evaluate the given integral using WolframAlpha. What do you observe?

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